(Paper) CCNA : Some Important Question & Answer Part - 2
Submitted by guru on Thu, 06/19/2008 - 10:23
PAPER : Some Important Question & Answer CCNA (Part - 2)
- The Cisco IOS global
configuration command “router igrp xxx” is used to configure the
Interior Gateway Routing Protocol. In this case, the 109 is called the
process-id , which can also be used for an autonomous system number. IGRP
supports a feature that allows traffic to be distributed among up to 6 (4
default) paths to provide greater overall throughput and reliability. What
is this called?
* unequal-cost load balancing
* equal-cost load balancing
* proportionate load balancing
* low cost load balancing
Correct answer: A
- An unequal-cost load balancing
is used to provide alternate paths for data distribution on an internetwork.
Cisco developed this method to use unused or under utilized links to
increase bandwidth and network availability. IGRP
uses flash updates, poison reverse updates, holddown times, and split
horizon. How often does it broadcast its routing table updates?
* 90 seconds
* 10 seconds
* 30 seconds
* 45 seconds
Correct answer: A
- The command “show IP protocol”
displays which information?
* routing timers
* network information
* contents of the IP routing table
* information about all known network and subnetworks
Correct answer: A & B
- “show IP protocol”
displays routing timers and network information. “show IP route”
displays the routing table with information about all known networks and
subnetworks. When using RIP, routing updates
are broadcast every ____ seconds.
* 30
* 10
* 60
* 90
Correct answer: A
- Novell’s RIP updates routing
tables every 60 seconds, Apple’s RTMP is every 10 seconds, routers ARP
every 60 seconds, DECnet hosts and IGRP signal every 15 seconds, and Banyan
VINES signals every 90 seconds. An autonomous
system can only exist if all routers in that system meet which criteria?
* interconnected
* run the same routing protocol
* assigned same autonomous system number
* run IGRP only
* run RIP only
Correct answer: A,B &C
- An autonomous system is a set
of routers and networks under the same administration. Each router must be
interconnected, run the same routing protocol, and assigned the same
autonomous system number. The network Information Center (NIC) assigns a
unique autonomous system number to enterprises. A
default route is analogous to a _________.
* default gateway
* static route
* dynamic route
* one-way route
Correct answer: A
- A default route is analogous
to a default gateway. It is used to reduce the length of routing tables and
to provide complete routing capabilities when a router might not know the
routes to all other networks. Routers can learn
about destinations through static routes, default, or dynamic routing. By
default, a router will use information derived from __________.
* IGRP
* RIP
* IP
* TCP
Correct answer: A
- The quality of information is rated:
Connected interface 0
Static route 1
IGRP 100
RIP 120
Unknown 255
The lower the value, the more reliable the source with 255 signifying information that the router will ignore. So, the router will use IGRP, rated at 100, before RIP, rated at 120.
You are logged into a router, what command would show you the IP addresses of routers connected to you?
* show cdp neighbors detail
* show run
* show neighbors
* show cdp
Correct answer: A
- As a system administrator, you
perform an extended ping at the privileged EXEC prompt. As part of the
display, you see “Set DF bit in IP header? [yes] :” What would happen if
you answered no at the prompt.
* This lets the router fragment the packet.
* It tells the router not to fragment the packet.
* This lets the router direct the packet to the destination it finds in its routing table.
* It tell the router to send the packet to the next hop router
Correct answer: A
- “Set DF bit in IP header?”
is a response to an extended ping at the router. If you answer yes (the
default) the router will not fragment the packet. If you answer no, the
router will fragment the packet. You have typed
“ping” 172.16.101.1 and get the following display: Type escape sequence
to abort.
Sending 5, 100-byte ICMP Echoes to 172.16.101.1, timeout is 2 seconds:
.!!!!
What does the “.” signify?
* That one message timed out.
* That all messages were successful.
* That one message was successful.
* That one message completed in under the allotted timeframe.
Correct answer: A
- The possible responses from the ping
command are: ! Successful receipt of an echo reply. Timed out waiting for a
reply U Destination unreachable C Congestion-experienced packet I Ping
interrupted ? Packet type unknown & Packet TTL exceeded Which command,
that is used to test address configuration, uses Time-To-Live (TTL) values
to generate messages from each router.
* trace
* ping
* telnet
* bootp
Correct answer: A
- The Cisco IOS EXEC command
“trace [protocol] [destination]” is used to discover routes that packets
will travel to their destination hosts. Trace uses TTL (Time to Live) values
to report destination route information. What does the
command “IP name-server 255.255.255.255″ accomplish?
* It sets the domain name lookup to be a local broadcast.
* This is an illegal command.
* It disables domain name lookup.
* The command is now defunct and has been replaced by “IP server-name ip any”
Correct answer: A
- By default DNS is enabled on a
router with a server address of 255.255.255.255, which provides for a local
broadcast. As a system administrator, you need to provide your routers with
a Domain Name System (DNS) server. How many DNS servers can you specify with
one command?
* 6
* 1
* 2
* 4
Correct answer: A
- You can only specify six name
servers in one command. The syntax is “IP name-server server-address1 [[
server-address2 ]…server-address6]. You must also enable DNS. How
would you configure one host name that points to two IP addresses?
* IP host jacob 1.0.0.5 2.0.0.8
* IP jacob 1.0.0.5 2.0.0.8
* IP host jacob 1.0.0.5
* IP host duplicate “all”
Correct answer: A
- The correct syntax is IP host name [
TCP-port-number ] address [ address ]….. So, “IP host P1R1 1.0.0.5
2.0.0.8″ is the correct choice. “IP host jacob 1.0.0.5″ only
points the host name jacob to one IP address–1.0.0.5.The following
selections show the command prompt and the configuration of the IP network
mask. Which two are correct?
* Router#term IP netmask-format { bitcount | decimal | hexadecimal }
* Router(config-if)#IP netmask-format { bitcount | decimal | hexadecimal }
* Router(config-if)#netmask-format { bitcount | decimal | hexadecimal }
* Router#ip netmask-format { bitcount | decimal | hexadecimal }
Correct answer: A & B
- Router#term IP netmask-format
{ bitcount | decimal | hexadecimal } and Router(config-if)#IP netmask-format
{ bitcount | decimal | hexadecimal } are correct. You can configure the mask
for the current session and you can configure it for a specific line.
When configuring the subnet mask for an IP address,
which formats can be used?
* dotted-decimal.
* Hexadecimal
* Bit-count
* Octal
* Binary
Correct answer: A, B &C
- You are given the following address:
153.50.6.27/25. Determine the subnet mask, address class, subnet address,
and broadcast address.
* 255.255.255.128, B,153.50.6.0, 153.50.6.127
* 255.255.255.128, C,153.50.6.0, 153.50.6.127
* 255.255.255.128, C,153.50.6.127, 153.50.6.0
* 255.255.255.224, C,153.50.6.0, 153.50.6.127
Correct answer: A
- You are given the following address:
128.16.32.13/30. Determine the subnet mask, address class, subnet address,
and broadcast address.
* 255.255.255.252, B,128.16.32.12, 128.16.32.15
* 255.255.255.252, C,128.16.32.12, 128.16.32.15
* 255.255.255.252, B,128.16.32.15, 128.16.32.12
* 255.255.255.248, B,128.16.32.12, 128.16.32.15
Correct answer: A
- You are given the following address:
15.16.193.6/21. Determine the subnet mask, address class, subnet address,
and broadcast address.
* 255.255.248.0, A, 15.16.192.0, 15.16.199.255
* 255.255.248.0, B, 15.16.192.0, 15.16.199.255
* 255.255.248.0, A, 15.16.199.255, 14.15.192.0
* 255.255.242.0, A, 15.16.192.0, 15.16.199.255
Correct answer: A
- You have an IP host address of
201.222.5.121 and a subnet mask of 255.255.255.248. What is the broadcast
address?
* 201.222.5.127
* 201.222.5.120
* 201.222.5.121
* 201.222.5.122
Correct answer: A
- The easiest way to calculate
this is to subtract 255.255.255.248 (subnet mask) from 255.255.255.255, this
equals 7. Convert the address 201.222.5.121 to binary–11001001 11011110
00000101 01111001. Convert the mask 255.255.255.248 to binary–11111111
11111111 11111111 11111000. AND them together to get: 11001001 11011110
01111000 or 201.222.5.120. 201.222.5.120 is the subnet
address, add 7 to this address for 201.222.5.127 or the broadcast address.
201.222.5.121 through 201.222.5.126 are the valid host addresses. Given
the address 172.16.2.120 and the subnet mask of 255.255.255.0. How many
hosts are available?
* 254
* 510
* 126
* 16,372
Correct answer: A
- 172.16.2 120 is a standard
Class B address with a subnet mask that allows 254 hosts. You are a network
administrator and have been assigned the IP address of 201.222.5.0. You need
to have 20 subnets with 5 hosts per subnet. The subnet mask is
255.255.255.248. Which addresses are valid host
addresses?
* 201.222.5.17
* 201.222.5.18
* 201.222.5.16
* 201.222.5.19
* 201.222.5.31
Correct answer: A,B & D
- Subnet addresses in this
situation are all in multiples of 8. In this example, 201.222.5.16 is the
subnet, 201.22.5.31 is the broadcast address. The rest are valid host IDs on
subnet 201.222.5.16. You are a network administrator
and have been assigned the IP address of 201.222.5.0. You need to have 20
subnets with hosts per subnet. What subnet mask
will you use?
* 255.255.255.248
* 255.255.255.128
* 255.255.255.192
* 255.255.255.240
Correct answer: A
- By borrowing 5 bits from the
last octet, you can. have 30 subnets. If you borrowed only 4 bits you could
only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing 4
bits, you have (2×2x2×2)-2=14. By borrowing 5 bits, you have (2×2x2×2x2)-2=30.
To get 20 subnets, you would need to borrow 5 bits so the subnet mask would
be 255.255.255.248. You are given the IP
address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the
network address in binary?
* 10101100 00010000
* 00000010 10100000
* 10101100 00000000
* 11100000 11110000
Correct answer: A
- To find the network address,
convert the IP address to binary–10101100 000100000 00000010
10100000–then ANDed it with the subnet mask–11111111 11111111 00000000
00000000. The rest is 10101100 00010000 00000000 00000000, which is
172.16.0.0 in decimal. The first octet rule states that the class of an
address can be determined by the numerical value of the first octet. Which
addresses are INCORRECTLY paired with their class?
* 128 to 191, Class B
* 192 to 223 Class B
* 128 to 191, Class C
* 192 to 223, Class C
Correct answer: B & C
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